Find the number which is nearest to 3105 and is exactly divisible by 21.
Soln:
On dividing 3105 by 21, we get 18 as remainder
Thus number to be added to 3105= 21-18 =3
Hence, required number = 3105 + 3 = 3108
Soln:
On dividing 3105 by 21, we get 18 as remainder
Thus number to be added to 3105= 21-18 =3
Hence, required number = 3105 + 3 = 3108
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